Pentagon Area Calculator
Press Calculate to see the area, the working and other units.
Find the area of a pentagon or any other 5-sided shape. For an irregular pentagon, enter the five sides and two diagonals drawn from one corner. For a regular pentagon, one side is enough.
Five sides do not fix the area of an irregular pentagon. Like a loop of hinged rods, a 5-sided outline can flex into many shapes while every side keeps its length, and each shape encloses a different area. Any calculator that accepts only five side lengths is assuming a shape you did not give it. This one asks for two diagonals as well, because they make the shape rigid and the answer exact.
Formula
A = T₁ + T₂ + T₃
- T₁
- the triangle made by sides a and b with diagonal p
- T₂
- the triangle made by diagonals p and q with side c
- T₃
- the triangle made by sides d and e with diagonal q
Each triangle's area comes from Heron's formula. A regular pentagon has a shorter route: A = ¼ × √(5(5 + 2√5)) × s².
Irregular pentagon: 5 sides and 2 diagonals
Choose one corner and label it A. Going around the shape from A, the sides are a, b, c, d and e. From A, two diagonals reach the two corners that are not next to it: p ends where b meets c, and q ends where c meets d. That divides the pentagon into three triangles, and a triangle cannot flex.
With sides of 30, 25, 20, 30 and 25 and diagonals of 45 and 40, the three triangles come to about 353.55, 399.95 and 374.53, for a total of about 1,128.04. Both diagonals must start from the same corner. If the calculator reports that some lengths cannot form a triangle, a diagonal has usually been measured from the wrong corner or the sides have been entered out of order.
Why 5 sides are not enough
Compare two shapes with every side equal to 10. The regular pentagon covers about 172.05. A house outline, made of a 10 by 10 square topped with an equilateral triangle, covers 100 + 43.30 = 143.30. Its diagonals from a bottom corner are about 14.14 and 19.32, and entering those gives the same 143.30. Same five sides, about 17% less area. Any single formula based on sides alone would be wrong for at least one of these.
Regular pentagon: the side alone
When all five sides and all five angles are equal, a single length settles everything. Multiply the side squared by ¼√(5(5 + 2√5)), which is about 1.7205. A regular pentagon with sides of 10 has an area of about 172.05, a perimeter of 50 and diagonals of about 16.18, since the diagonal is the side times the golden ratio, about 1.618.
Equal sides alone do not make a pentagon regular, as the house outline shows. The angles must match too, each one 108°. If you are unsure, measure a diagonal or two: on a regular pentagon they are all the same length, and if they are not, use the irregular method.
- A = ¼ × √(5(5 + 2√5)) × s²
- A ≈ 1.7205 × s²
Using it on real shapes
Five-sided outlines are common in lots with one clipped corner, rooms with a bay wall, and gable-end walls, which are the house outline at a larger scale. A tape is all you need, since no angles are involved. Pick a corner from which both diagonals run inside the shape, and if one has to pass outside because a corner points inward, try another corner. For a shape with six or more corners, or if a diagonal is blocked by a building, listing corner coordinates in the irregular shape calculator is the better route.
Frequently asked questions
How do I find the area of an irregular pentagon?
Cut it into three triangles with two diagonals from one corner, find each area with Heron's formula, and add them. Enter the five sides and two diagonals above and the calculator does this for you.
Can I find a pentagon's area from 5 sides alone?
Not unless it is regular. An irregular 5-sided shape can flex while its sides stay the same, which changes the area. You need at least two more measurements, such as two diagonals.
What is a 5-sided shape called?
A 5-sided shape is a pentagon, whether or not its sides match. Regular means all sides and angles are equal, and irregular covers everything else.
What is the formula for a regular pentagon?
A = ¼ × √(5(5 + 2√5)) × s², or about 1.7205 × s². A side of 6 gives about 61.94.
What if I measure the diagonals from different corners?
The method needs both from one corner, since that is what splits the shape into three triangles. Diagonals from two corners would cross inside the shape and give the wrong result.
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